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voltage regulator for middle output current r 5re series application manual no.ea-016-0006
voltage regulator for middle output current 1 r 5re series outline the r 5re series are voltage regulator ics with high output voltage accuracy and ultra-low quiescent current by cmos process. each of these ics consists of a voltage reference unit, an error amplifier, a driver transistor, and resistors for setting output voltage, and a current limit circuit. by use of these ics, a con- stant voltage power supply circuit with high efficiency can be constructed because the dropout voltage and quiescent current of these ics are very small. furthermore, theses ics have a built-in current limit circuit. the output voltage of these ics is fixed with high accuracy. two types of packages, to-92 and sot-89 (mini-power mold) are available. ? ultra-low quiescent current ........................... typ. 1.1a (r 5re30a,v in =5.0v) ? ultra-low dropout voltage ............................... typ. 0.5v (r 5re50a,i out =60ma) ? large output current ...................................... typ. 120ma (r 5re50a) ? low temperature-drift coefficient of output voltage ........................... typ. 100ppm/?c ? broad operating voltage range ...................... max. 10.0v ? excellent line regulation ................................ typ. 0.1%/v ? high accuracy output voltage ........................ 2.5% ? output voltage ................................................... stepwise setting with a step of 0.1v in the range of 2.0v to 6.0v is possible (refer to selection guide) ? two types of packages .................................. to-92, sot-89 (mini-power mold) features applications ? power source for battery-powered equipment. ? power source for cameras, video instruments such as camcorders, vcrs, and hand- held communication equipment. ? precision voltage references. block diagram 2 1 3 vref v out gnd v in +
2 r 5re C ? part number ----- abcde selection guide the package type, the output voltage, the packing type, and the taping type of r 5re series can be designated at the user's request by specifying the part number as follows. } } for example, the product with package type sot-89,output voltage 5.0v,version a and taping type t1 are designated by part number rh5re50aa-t1. code contents designation of package type: a e: to-92 h: sot-89 (mini-power mold) b setting output voltage (v out ): stepwise setting with a step of 0.1v in the range of 2.0v to 6.0v is possible. ca designation of packing type: d a: taping c: antistatic bag for to-92 and samples designation of taping type: ex. to-92 : rf, rr, tz e sot-89: t1, t2 (refer to taping specifications) tz and t1 are prescribed as a standard. r 5re
3 ? to-92 pin configuration ? sot-89 pin description ? to-92 ? sot-89 pin no. symbol 1 gnd 2v in 3v out pin no. symbol 1 gnd 2v in 3v out 12 3 (mark side) 12 3 (mark side) r 5re
4 absolute maximum ratings symbol item v in input voltage v out output voltage i out output current p d power dissipation topt operating temperature tstg storage temperature tsolder lead temperature (soldering) rating unit +12 v C0.3 to v in +0.3 v 300 ma 300 mw C40 to +85 ?c C55 to +25 ?c 260?c, 10s r 5re absolute maximum ratings are threshold limit values that must not be exceeded even for an instant under any conditions. moreover, such values for any two items must not be reached simultaneously. operation above these absolute maximum ratings may cause degradation or permanent damage to the device. these are stress ratings only and do not necessarily imply functional operation below these limits. absolute maximum ratings
5 electrical characteristics symbol item v out output voltage i out output current ? v out load regulation ? i out v dif dropout voltage i ss quiescent current ? v out ? v in line regulation v in input voltage ilim current limit ? v out output voltage ? topt temperature coefficient conditions min. typ. max. unit v in =4.0v,i out =10ma 1.950 2.000 2.050 v v in =4.0v 40 60 ma v in =4.0v 1ma i out 50ma 40 80 mv i out =30ma 0.5 0.7 v v in =4.0v 1.0 3.0 a i out =10ma v out + 1.0v v in 10v 0.1 %/v 10 v 240 ma i out =10ma 100 ppm/?c C40?c topt 85?c topt=25?c ? r 5re30a topt=25?c r 5re symbol item v out output voltage i out output current ? v out load regulation ? i out v dif dropout voltage i ss quiescent current ? v out ? v in line regulation v in input voltage ilim current limit ? v out output voltage ? topt temperature coefficient conditions min. typ. max. unit v in =5.0v,i out =10ma 2.925 3.000 3.075 v v in =5.0v 50 80 ma v in =5.0v 1ma i out 60ma 40 80 mv i out =40ma 0.5 0.7 v v in =5.0v 1.1 3.3 a i out =10ma v out +1.0v v in 10v 0.1 %/v 10 v 240 ma i out =10ma 100 ppm/?c C 40 ?c topt 85 ?c
6 ? r 5re50a topt=25?c r 5re ? r 5re40a topt=25?c symbol item v out output voltage i out output current ? v out load regulation ? i out v dif dropout voltage i ss quiescent current ? v out ? v in line regulation v in input voltage ilim current limit ? v out output voltage ? topt temperature coefficient conditions min. typ. max. unit v in =6.0v,i out =10ma 3.900 4.000 4.100 v v in =6.0v 65 100 ma v in =6.0v 1ma i out 70ma 40 80 mv i out =50ma 0.5 0.7 v v in =6.0v 1.2 3.6 a i out =10ma v out +1.0v v in 10v 0.1 %/v 10 v 240 ma i out =10ma 100 ppm/?c C 40 ?c topt 85 ?c symbol item v out output voltage i out output current ? v out load regulation ? i out v dif dropout voltage i ss quiescent current ? v out ? v in line regulation v in input voltage ilim current limit ? v out output voltage ? topt temperature coefficient conditions min. typ. max. unit v in =7.0v,i out =10ma 4.875 5.000 5.125 v v in =7.0v 80 120 ma v in =7.0v 1ma i out 80ma 40 80 mv i out =60ma 0.5 0.7 v v in =7.0v 1.3 3.9 a i out =10ma v out +1.0v v in 10v 0.1 %/v 10 v 240 ma i out =10ma 100 ppm/?c C40?c topt 85?c
7 ? r 5re60a topt=25?c r 5re symbol item v out output voltage i out output current ? v out load regulation ? i out v dif dropout voltage i ss quiescent current ? v out ? v in line regulation v in input voltage ilim current limit ? v out output voltage ? topt temperature coefficient conditions min. typ. max. unit v in =8.0v,i out =10ma 5.850 6.000 6.150 v v in =8.0v 80 120 ma v in =8.0v 1ma i out 80ma 40 80 mv i out =60ma 0.5 0.7 v v in =8.0v 1.4 4.2 a i out =10ma v out +1.0v v in 10v 0.1 %/v 10 v 240 ma i out =10ma 100 ppm/?c C40?c topt 85?c
8 electrical characteristics by output voltage r 5re v in C v out =2.0v 1ma 40 60 i out 50ma v in C v out =2.0v 1ma i out 60ma 50 80 v in C v out =2.0v 40 80 1ma i out 70ma 65 100 v in C v out =2.0v 1ma 80 120 i out 80ma r 5re20a 1.950 2.000 2.050 r 5re21a 2.048 2.100 2.152 r 5re22a 2.145 2.200 2.255 r 5re23a 2.243 2.300 2.357 r 5re24a 2.340 2.400 2.460 r 5re25a 2.438 2.500 2.562 r 5re26a 2.535 2.600 2.665 r 5re27a 2.633 2.700 2.767 r 5re28a 2.730 2.800 2.870 r 5re29a 2.828 2.900 2.972 r 5re30a 2.925 3.000 3.075 r 5re31a 3.023 3.100 3.177 r 5re32a 3.120 3.200 3.280 r 5re33a 3.218 3.300 3.382 r 5re34a 3.315 3.400 3.485 r 5re35a 3.413 3.500 3.587 r 5re36a 3.510 3.600 3.690 r 5re37a 3.608 3.700 3.792 r 5re38a 3.705 3.800 3.895 r 5re39a 3.803 3.900 3.997 r 5re40a 3.900 4.000 4.100 r 5re41a 3.998 4.100 4.202 r 5re42a 4.095 4.200 4.305 r 5re43a 4.193 4.300 4.407 r 5re44a 4.290 4.400 4.510 r 5re45a 4.388 4.500 4.612 r 5re46a 4.485 4.600 4.715 r 5re47a 4.583 4.700 4.817 r 5re48a 4.680 4.800 4.920 r 5re49a 4.778 4.900 5.022 r 5re50a 4.875 5.000 5.125 r 5re51a 4.973 5.100 5.227 r 5re52a 5.070 5.200 5.330 r 5re53a 5.168 5.300 5.432 r 5re54a 5.265 5.400 5.535 r 5re55a 5.363 5.500 5.637 r 5re56a 5.460 5.600 5.740 r 5re57a 5.558 5.700 5.842 r 5re58a 5.655 5.800 5.945 r 5re59a 5.753 5.900 6.047 r 5re60a 5.850 6.000 6.150 output voltage outputcurrent load regulation part number v out (v) i out (ma) ? v out / ? i out (mv) conditions min. typ. max. conditions min. typ. conditions typ. max. v in C v out =2.0v i out =10ma v in C v out =2.0v i out =30ma i out =40ma 0.5 0.7 i out = 50ma i out =60ma dropout voltage v dif (v) conditions typ. max.
9 r 5re topt=25?c 1.0 3.0 1.1 3.3 i out =10ma i out v in C =10ma v out 1.2 3.6 0.1 10 240 100 =2.0v v out + C40?c 1.0v topt v in 85?c 10v 1.3 3.9 1.4 4.2 quiescent current line regulation input voltage current limit output voltage tempco. iss(a) ? v out / ? v in (%/v) v in (v) ilim(ma) ? v out / ? t(ppm/?c) conditions typ. max. conditions typ. max. typ. conditions typ.
10 operation output voltage v out divided at the node between registers r1 and r2 is compared with reference voltage by error amplifier, so that a constant voltage is output. test circuits fig. 2 test circuit fig. 3 quiescent current test circuit fig. 4 line transient response test circuit fig. 1 brock diagram r 5re gnd gnd v in + error amplifire v out r2 r1 vref c i 1? co 1? v in gnd r 5re series v out i out v out v in + + i ss c i 1? v in gnd r 5re series v out v in + ro co 0.1? p.g gnd r 5re series v out v out v in +
11 typical characteristics 1) output voltage vs. output current r 5re40a r 5re50a r 5re50a r 5re output current i out (ma) output voltage v out (v) 0 3.7 3.8 3.9 4.1 4.0 v in =6.0v 50 100 150 200 topt=?0?c 85?c 25?c 4.7 4.8 4.9 5.1 5.0 v in =7.0v 0 50 100 150 200 250 output voltage v out (v) output current i out (ma) with heatsink without heatsink 4.7 4.8 4.9 5.1 5.0 v in =7.0v 0 50 100 150 200 250 heatsink 30 30 1mm output voltage v out (v) output current i out (ma) 4.7 4.8 4.9 5.1 5.0 v in =7.0v 0 50 100 150 200 250 300 350 25?c topt=?0?c 85?c r 5re30a output voltage v out (v) output current i out (ma) 2.7 2.8 2.9 3.1 3.0 v in =5.0v 0 50 100 150 200 250 topt= ?0?c 25?c 85?c r 5re20a 2) output voltage vs. input voltage i out =1? topt=25?c 1.0 3.0 4.0 2.0 5.0 input voltage v in (v) 1ma 10ma output voltage v out (v) 1.0 1.2 0.8 1.4 1.6 1.8 2.0 2.2 2.4 topt=25?c 245 367 input voltage v in (v) output voltage v out (v) 1.98 1.96 2.00 2.02 2.04 i out =1? 1ma 10ma
12 r 5re30a r 5re40a r 5re30a r 5re40a r 5re r 5re50a r 5re50a topt=25?c 2.0 3.0 3.5 2.5 4.0 4.5 input voltage v in (v) output voltage v out (v) 2.0 2.2 1.8 2.4 2.6 2.8 3.0 3.2 3.4 i out =1ma 50ma 10ma 2.5 4.5 3.5 5.5 input voltage v in (v) topt=25?c output voltage v out (v) 3.4 3.2 3.6 3.8 4.0 4.2 i out =1ma 50ma 10ma topt=25?c 3.0 5.0 6.0 4.0 7.0 8.0 input voltage v in (v) output voltage v out (v) 2.96 2.95 2.97 2.98 2.99 3.00 i out =1? 1ma 10ma topt=25?c 467 589 input voltage v in (v) output voltage v out (v) 3.98 3.96 4.00 4.02 4.04 4.06 1ma i out =1? 10ma topt=25?c 4.5 4.0 5.5 6.0 5.0 6.5 input voltage v in (v) output voltage v out (v) 4.4 4.2 4.6 4.8 5.0 5.1 i out =1ma 50ma 10ma topt=25?c 6 589 710 input voltage v in (v) output voltage v out (v) 4.97 4.98 4.95 4.96 4.99 5.00 5.01 5.02 5.03 5.04 5.05 10ma i out =1? 1ma
13 r 5re30a r 5re40a r 5re50a 3) dropout voltage vs. output curret r 5re output current i out (ma) dropout voltage v dif (v) 0 20 40 60 80 100 topt=?0?c 25?c 85?c 0.0 0.4 0.6 0.2 0.8 1.0 1.2 1.4 output current i out (ma) dropout voltage v dif (v) 0 20 40 60 80 100 85?c 25?c topt= ?0?c 0.0 0.4 0.5 0.7 0.6 0.2 0.3 0.1 0.8 output current i out (ma) dropout voltage v dif (v) 0 20 40 60 80 100 0.0 0.2 0.4 0.6 0.8 1.0 25?c topt=?0?c 85?c r 5re30a 4) output voltage vs.temperature temperature topt(?c) output voltage v out (v) -50-30-101030507090 2.9 3.0 3.1 i out =10ma r 5re40a temperature topt(?c) output voltage v out (v) 3.9 4.0 4.1 -50-30-101030507090 i out =10ma
14 r 5re50a r 5re20a 5) quiescent current vs. input voltage r 5re r 5re40a r 5re50a temperature topt(?c) output voltage v out (v) 4.9 4.8 5.0 5.2 5.1 -50-30-101030507090 i out =10ma input voltage v in (v) 0.6 345678 910 0.7 0.8 0.9 1.0 1.1 quiescent current iss(?) topt=25?c r 5re30a input voltage v in (v) 1.0 24 3 5678910 1.1 1.2 1.3 1.4 quiescent current iss(?) topt=25?c input voltage v in (v) 1.0 46 5 7 8 9 10 11 1.1 1.2 1.3 1.4 1.5 quiescent current iss(?) topt=25?c input voltage v in (v) 0.5 0.6 7 6 589101112 0.7 0.8 0.9 1.0 1.1 1.2 1.3 1.5 1.4 quiescent current iss(?) topt=25?c
15 r 5re20a r 5re50a r 5re40a 6) quiescent current vs. temperature r 5re 0.5 0.7 0.9 1.1 1.3 1.7 1.5 quiescent current iss(?) v in =4.0v ?0 ?0 0 20 40 60 80 100 temperature topt(?c) 0.5 0.7 0.9 1.1 1.3 1.7 1.5 quiescent current iss(?) v in =6.0v ?0 ?0 0 20 40 60 80 100 temperature topt(?c) r 5re30a 0.8 1.0 1.2 1.6 1.4 quiescent current iss(?) v in =5.0v ?0 ?0 0 20 40 60 80 100 temperature topt(?c) v in =7.0v 0.5 0.7 0.6 0.8 0.9 1.0 1.2 1.1 1.5 1.3 1.4 quiescent current iss(?) ?0 ?0 0 20 40 60 80 100 temperature topt(?c) 7) dropout voltage vs. set output voltage r 5re series 012 34 56 0.0 0.2 0.1 0.3 0.4 0.5 0.6 0.7 set output voltage vreg(v) dropout voltage v dif (v) 1ma topt=25?c 10ma i out =50ma
16 8) line transient response (1) r 5re r 5re30a r 5re40a r 5re20a r 5re50a 9) line transient response (2) r 5re20a r 5re30a 1.5 2.0 2.5 3.0 3.5 4.0 4.5 1.0 2.0 1.5 2.5 3.0 4.5 4.5 3.5 5.0 input voltage/output voltage v(v) i out =1ma time t(ms) input voltage output voltage 1.5 2.0 2.5 3.0 3.5 4.0 4.5 2.0 4.0 3.0 5.0 7.0 6.0 8.0 input voltage/output voltage v(v) i out =1ma time t(ms) input voltage output voltage 1.5 2.0 2.5 3.0 3.5 4.0 4.5 1.0 3.0 2.0 4.0 6.0 5.0 7.0 input voltage/output voltage v(v) i out =1ma time t(ms) input voltage output voltage 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 output voltage 3.0 5.0 4.0 6.0 8.0 7.0 9.0 input voltage/output voltage v(v) i out =1ma time t(ms) input voltage 1.5 2.0 2.5 3.0 3.5 4.0 4.5 0.0 1.0 1.5 0.5 2.0 2.5 4.0 4.5 3.5 3.0 5.0 input voltage/output voltage v(v) i out =30ma time t(ms) input voltage output voltage 1.5 2.0 2.5 3.0 3.5 4.0 4.5 1.0 3.0 2.0 4.0 6.0 5.0 7.0 input voltage/output voltage v(v) i out =30ma time t(ms) input voltage output voltage
17 r 5re40a r 5re50a r 5re 1.5 2.0 2.5 3.0 3.5 4.0 4.5 2.0 4.0 3.0 5.0 7.0 6.0 8.0 input voltage/output voltage v(v) i out =30ma time t(ms) input voltage output voltage i out =30ma 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 output voltage 3.0 5.0 4.0 6.0 8.0 7.0 9.0 input voltage/output voltage v(v) time t(ms) input voltage
18 typical application in r 5re series, a constant voltage can be obtained without using capacitors c1 and c2. however, when the wire connected to v in is long, use capacitor c1. output noise can be reduced by using capacitor c2. insert capacitors c1 and c2 with the capacitance of 0.1f to 2.0f between input/output pins and gnd pin with minimum wiring. the output voltage can be obtained by the follow- ing formula : v out =vreg (1+r2/r1) + i ss r2 since the quiescent current of r 5re series is so small that the resistances of r1 and r2 can be set as large as several hundreds k and therefore the sup- ply current of voltage boost circuit itself can be reduced. furthermore, since r 5re series are operated by a constant voltage, the supply current of voltage boost circuit is not substantially affected by the input voltage. as shown in the circuit diagram, a dual power sup- ply circuit can be constructed by using two r 5re series. this circuit diagram shows a dual power supply circuit with an output of 3v and an output of 5v. when the minimum output current of ic2 is larger than i ss of ic1, resistor r is unnecessary. diode d is a protection diode for the case where v out 2 becomes larger than v out 1. ? voltage boost circuit ? dual power supply circuit r 5re c2 c1 v in gnd gnd gnd r 5re series v out v out v in + + c2 c1 v in gnd gnd r 5re series v out v out v in r1 r2 i ss + + c1 c2 v in gnd gnd gnd r 5re20a r 5re30a v out v out 1 5v v out 2 3v v in c3 gnd v out v in r i ss ic1 ic2 d + + + * 1) vreg : set output voltage of r 5re series. * 1 application circuits
19 ? current boost circuit output current of 120ma or more can be obtained by the current boost circuit constructed as shown in this circuit diagram. ? current boost circuit with overcurrent limit circuit ? current source a current source with the structure as shown in this circuit diagram can be used. output current i out is obtained as follows : i out =vreg /r + i ss take care that output current i out does not exceed its allowable current. r 5re c2 gnd gnd gnd r 5re series v out v out c1 v in v in tr.1 + + c2 gnd gnd gnd r 5re series v out v out v in v in tr.1 tr.2 r1 r2 i out vbe2 + + gnd r 5re series c1 v in v in r i out i ss v out + a circuit for protecting tr.1 from the destruction caused by output short-circuit or overcurrent is shown in this circuit diagram. when the voltage reduction caused by the current ( aa i out ) which flows through r2 reaches vbe2 of tr.2 by additionally providing the current boost circuit with tr.2 and r2, tr.2 is turned on and the base current of tr.1 is increased, so that the output current is limited. current limit of overcurrent limit circuit is obtained as follows : i out vbe2/r2 * 1) vreg : set output voltage of r 5re series. * 1

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